Thứ Sáu, 7 tháng 2, 2014

Tài liệu Chapter XVIII Diffraction of light pdf

a
b
For analyzing this phenomenon, we use the Huyghen-Fresnel principle.
1.2 Huygen-Fresnel principle:
For analyzing properties of wave processes, Huygen introduced the
concept of wave front, and the rule how to draw a wave front from
known sharp of at some former time
 Huygen’s principle (1678):
All points on wavefront are point
sources for spherical secondary
wavelets with speed, frequency
that equal to initial wave. The wave front at a
later time is the envelope of these wavelets.
Wavefront at
t=0
Wavefront at
time t
Basing on Huygen’s principle one can interpret diffraction as
interference of light from secondary sources. For example, every
point of circular aperture becomes a secondary source, and what we
see in the screen is the interference of secondary sources.
But this interpretation is only qualitively, for a quantitive analyze,
we need more. It has not been known from Huygen’s principle:
how can determine the amplitude and the phase of secondary waves ?
 Fresnel’s complementary statement:
Observation
point
Wave
front
 Fresnel states that for the vibration
at P due to waves from the secondary
source dS we have the following formula:
dS
where

a
0
&
(t + 

)
→ the amplitude &
phase of vibration of secondary sources at dS on the wave front S

K
→ a coefficient which depends on the angle


K
decreases
as

increases;
K = 0
when

= / 2
 The total vibration
at
P
is
1.3 Analysis of diffraction through circular aperture:
Having Huygen-Fresnel principle we tend to analyze the phenomenon
of diffraction through a circular aperture.
1.3.1. The Frsenel method to devide a spherical wave front into
adjacent zones (Fresnel zones):
1-th zone
2-nd zone
3-rd zone
4-th zone
Calculate the area of the
m-th zone:
where S
m
is the area of
the m-th spherical segment:
(h
m
– the hight of segment)
h
m
is defined from the following equation:

Remark: The area of a zone does not depend on m. It means that the
areas of zones are approximatly the same (for values of m that are not
large).
We have also the formula for the radius of the m-zone:
r
m
is proportional to
From the Fresnel formula for dξand all the described properties of
Fresnel zones we can lead to the following formula for the amplitudes
of vibrations at P which are sent from Fresnel spherical zones :
from the 1-st zone
from the m-th zone
,,,

Further, the phases of vibrations from two adjacent zones have the
phase difference → we can write for the total amplitude of
vibrations at P:
It equals a half of amplitude due to
the 1-st zone !
1.3.2 Come back to the experiment of diffraction through an aperture:
→ What happens if there is a screen with circular aperture in the
light propagation line ?
Suppose that the part of wave front based on the aperture
incorporates m zones:
+ for odd m
- for even m
(odd m)
(even m)
Screen with aperture
Screen
y y
Conclusions of diffraction picture on the screen:
 Depending on the size of aperture, the number of open zones m is
odd or even:
• If m is odd → at the center point P there is a light spot
• If m is even → at the center point P there is a dark spot
 Besides the center point P, at other points in the screen, the light
intensity has maxima or minima, depending on the distance from
the center point P.
Owing to the symmetry, light & dark fringers on the screen are
circles centered at P.
Comparison the Fresnel zone pictures according to
a) the axis SP; b) the axis SP’; c) the axis SP”
a)
b)
c)
To understand why the light intensity is different at P, P’ & P”
we describe the Fresnel zones for three cases, and make a
comparison. Here we suppose that the aperture exposes 3 zones.

Không có nhận xét nào:

Đăng nhận xét